SAYING BYE TO LEMON & HI TO WATER! :D

As you have probably realised from reading my method that I have decided not to use lemon juice.
After doing intense mathematics during my double history I realised that when you add two solutions that both have a percentage acid of 5.....your solution will still have an % acid of 5.

So this is what i mean...

% of acid in Lemon = 5%

% of acid in Vinegar = 5%

∴ IN a solution of 100mL of lemon & 100mL of vinegar there will be 5mL of acid from the lemon & 5mL from the vinegar

∴The % of acid in the solution is: (5+5) x 100 = 5%

200

pft...so as a result I have decided to use water instead! Water has a 0% of acid! So if I add the two together i should have a % acid of 2.5%....

So this is what i mean...
% of acid in Water = 0%
% of acid in Vinegar = 5%
∴ IN a solution of 100mL of water & 100mL of vinegar there will be 0mL of acid from the water & 5mL from the vinegar
∴The % of acid in the solution is: (0+5) x 100 = 2.5%
200

So! Now that I have convinced myself so much that that works....even if it doesn't im goning through with it.
So now,
I'm going to have three solutions and this is what they're gona have in each:
'A' - Water solution (200mL of water) = 0% acid
'B' - Water/ Vinegar solution (100mL of vinegar + 100mL of water) = 2.5% acid (in theory)
'C' - Vinegar solution (200mL of vinegar) = 5% acid

with the hope of starting her experiment in good time,
Lakshmi